Density of gold is 19 gm / cm3 If 1 9x10-4 of gold is dispersed in 1 liter - Chemistry - Surface Chemistry

Question

Density of gold is 19 gm / cm3 If 1 9x10-4 of
gold is dispersed in 1 liter of water to give a sol having
spherical gold particles of radius 10nm, then the number of gold
particles per mm3 of the sol will be

Vartika Jain · Accepted Answer

Dear Student,

Density of gold = 19 gcm-3Mass of gold = 1
9×10-4 gVolume of gold=MassDensity=1
9×10-419=10-5 cm3Radius = 10 nm= 10-6 cmVolume of one gold particle = 43πr3= 43×(3
14)×(10-6)3                                                 =4
1866×10-18 cm3Now, no
 of gold sold particles in 10-5 cm3  =14
1866×10-18×10-5=2 38×1012So, no
 of gold sol particle in 1mm3 =2
38×1012106=2 38×106

Density of gold is 19 gm / cm3 . If 1.9x10-4 of gold is dispersed in 1 liter of water to give a sol having spherical gold particles of radius 10nm, then the number of gold particles per mm3 of the sol will be.

Density of gold is 19 gm / cm³. If 1.9x10^-4 of gold is dispersed in 1 liter of water to give a sol having spherical gold particles of radius 10nm, then the number of gold particles per mm³of the sol will be.