deravative of tan-1(sinx/1+cosx) Share with your friends Share 0 Priyanka Kedia answered this ddxtan-1sinx1+cosx=11+sinx1+cosx2ddxsinx1+cosx =1+cosx21+cosx2+sinx21+cosxddxsinx-sinxddx1+cosx1+cosx2 =11+cos2x+2cosx+sin2x1+cosxcosx-sinx-sinx1 =cosx+cos2x+sin2x1+2cosx+ cos2x+sin2x =cosx+11+2cosx+1 =cosx+12cosx+1 =12Hence, ddxtan-1sinx1+cosx =12 0 View Full Answer
