derivative of sin3x Share with your friends Share 1 Varun.Rawat answered this Let y = sin 3x put 3x = t , so, y = sin tdifferentiating both sides w.r.t. 't', we getdydt = cos tnow, t = 3xdifferentiating both sides w.r.t. 'x', we getdtdx = 3now, dydx = dydt × dtdx = cos t × 3 = 3 cos t = 3 cos 3x so, ddxsin 3x = 3 cos 3x 2 View Full Answer