Derive an expression for the kinetic energy of a body of mass (m) rotating uniformly about a given axis. Show that the rotational kinetic energy = 1/2M (L/K)^2 Where symbols have their usual meanings.

Dear Student,



Now,

Angular momentum: L=Iω...(i)or, ω2=LI2..(ii)Rot. K.E=12Iω2or, using (ii)K.E=12L2I...(iii)Now, from radius of gyrationI=MK2..(iv)  where K=radius of gyrationthus plugging this in (iii)Rot K.E= 12ML2K2


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