derive hardy-weinberg principle equation.

 Please answer this question ASAP....... my exam's on 12th.

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 Hardy Weinberg equation gives the relationship between allelic and genotypi frequencies in a population.

p is the probability of the dominant allele and q is that of the recessive allele for a particular trait controlled by 2 allels A and a.

i.e p is all of alleles in individuals with homozygous dominant genotype(AA) and half of individuals with heterozygous genotype(Aa).

like wise for q.

p=AA+1/2Aa  q=aa+1/2Aa

Since there are only 2 alleles here, p+q = 1.

hence the chances of all possible alleles occuring randomnly

(p+q)^2 ( p+q whole square) = 1

p^2 +2pq + q^2  =1.

where p^2 is the predicted frequency of homozygous dominant individuals(AA)

2pq  is the predicted frequency of heterozygous individuals.(Aa)

q^2 is the predicted frequency of homozygous reessiev individuals.(aa)

This can also be derived by using Punnett square.

  female

  A (p)  a(q)

male  A(p)    p^2  pq 

  a(q)  pq  q^2

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thank you...................

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