describe an activity with labelled diagram to show that a force acts on current carrying conductor placed in a magnetic field and its direction of current through conductor. name the rule which determines the direction of this force
Dear Student
(i) Hang the aluminium rod with the help of clamp stand such that it passes between the North and South pole of the magnet with the magnetic field directed upwards and the rod being horizontal and perpendicular to the field.
(ii)Connect the aluminium rod in series with a battery, a key and a rheostat.
(iii) Pass a current through the aluminium rod from one end to other (B to A).
(iv) The rod is displaced towards left.
(v) When the direction of current flowing through the rod is reversed, the displacement of rod is towards right.
This activity shows that
(i) Magnetic field exerts a force on a current carrying conductor.
(ii) The force exerted on the current carrying conductor depends upon the direction of current and direction of magnetic field acting on it.
(iii) Displacement of the rod or the magnetic force on it is largest when the direction of current is at right angle to the direction of magnetic field.
(iv) When current carrying conductor is placed parallel to the magnetic field, it experiences no force
(b) Direction of force experienced by a current carrying straight conductor placed in a magnetic field which is perpendicular to it is given by Fleming’s left hand rule. Stretch the thumb, forefinger and middle finger of left hand in such a way that they are mutually perpendicular to each other. If the forefinger points in the direction of magnetic field and the middle finger in the direction of current, then the thumb will point in the direction of motion or the force acting on the conductor.
Regards
(i) Hang the aluminium rod with the help of clamp stand such that it passes between the North and South pole of the magnet with the magnetic field directed upwards and the rod being horizontal and perpendicular to the field.
(ii)Connect the aluminium rod in series with a battery, a key and a rheostat.
(iii) Pass a current through the aluminium rod from one end to other (B to A).
(iv) The rod is displaced towards left.
(v) When the direction of current flowing through the rod is reversed, the displacement of rod is towards right.
This activity shows that
(i) Magnetic field exerts a force on a current carrying conductor.
(ii) The force exerted on the current carrying conductor depends upon the direction of current and direction of magnetic field acting on it.
(iii) Displacement of the rod or the magnetic force on it is largest when the direction of current is at right angle to the direction of magnetic field.
(iv) When current carrying conductor is placed parallel to the magnetic field, it experiences no force
(b) Direction of force experienced by a current carrying straight conductor placed in a magnetic field which is perpendicular to it is given by Fleming’s left hand rule. Stretch the thumb, forefinger and middle finger of left hand in such a way that they are mutually perpendicular to each other. If the forefinger points in the direction of magnetic field and the middle finger in the direction of current, then the thumb will point in the direction of motion or the force acting on the conductor.
Regards