Describe the state of hybridization, the shape and magnetic behavior of the following complex:  [Co(NH3)2(en)2]3+
(At no's: Co = 27)
 

The oxidation state of the metal is[Co(NH3)2 (en)2]3+ x + 0 = +3x= +3Co27 - 3d7 4s2Co3+ - 3d6As ammonia is a strong field ligand the pairing up of electrons takes placeand it shows d2sp3. The  molecule is existing with octahedral shape. From the hybridisation the complex formed is inner orbit complex. Magnetic moment μ = n(n+2)There is no unpaired electronMagnetic moment μ = 0(0+2)            = 0 BM
So its a diamagnetic complexes. 

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