determine the net force required to accelerate a 540 kg ultra light car from 0 to 27m/s in 10 sec.
Given,
m = 540 kg
u = 0
v = 27 m/s
t = 10 sec
We know,
v = u + at
27 = 0 + a * 10
27 = 10a
27/10 = a
a = 2.7 m/s2
Now,
F = m * a
F = 540 * 2.7
F = 1458 N
Therefore, the net force required to accelerate a 540 kg ultra light car from 0 to 27 m/s in 10 sec is 1458 N.
m = 540 kg
u = 0
v = 27 m/s
t = 10 sec
We know,
v = u + at
27 = 0 + a * 10
27 = 10a
27/10 = a
a = 2.7 m/s2
Now,
F = m * a
F = 540 * 2.7
F = 1458 N
Therefore, the net force required to accelerate a 540 kg ultra light car from 0 to 27 m/s in 10 sec is 1458 N.