Determine the point in XY plane which is equidistant from the points
A (1, –1, 0) B(2, 1, 2) and C(3, 2, –1)
let the required point on X-Y plane be P(x,y,0).
A (1, –1, 0) B(2, 1, 2) and C(3, 2, –1)
therefore PA=PB=PC
subtracting (2) from (1):
2y=2
y=2/2=1
2x+2*1=5
2x=5-2=3
x=3/2
thus the required point is (3/2 , 1,0 )
hope this helps you.
cheers!!