determine the sine angle of between the two vectors 3i+j+2k and 2i-2j+4k
Dear Student,
a = 3i + j + 2k
a = 3i + j + 2k
b = 2i - 2j + 4k
a x b = i(4+4) - j(12-4) + k(-6 -2)
= 8i - 8j - 8k
|axb| = (64 + 64 + 64)1/2
= (192)1/2
|a| = (9 + 1 + 4)1/2 = 141/2
|b| = (4 + 4 + 16)1/2 = 241/2
SinQ = |axb|/|a| |b|
=