Determine the value of x so that:

800 = 8*10x⁸*x^-3/2

^{its urgent please try to do it by today}

Answer :
            Determine the value of  'x'
           
             $800 = 8 * 10x^8 * x^{-\frac{3}{2}}$



Now, 
           $$\begin{gathered} x^8 * x^{-\frac{3}{2}}= \frac{800}{80} \\ {x}^{\left(8 + (-\frac{3}{2})\right)} = 10 \\ {x}^{\left(\frac{13}{2}\right)} = 10 (after taking L.C.M.) \end{gathered}$$

( From if we have $a^b = c therefore a= c^{\frac{1}{b}}$) or ( we can multiply both side in power by $\frac{2}{13}$ )
We get, 

            $x= (10{)}^{\frac{2}{13}}$        (Ans)