Diagonals AC and BD of trapezium ABCD with AB||DC intersect each other at O.
prove that ar(AOD) = ar (BOC)?
10.
Given that ABCD is a trapezium with AB || DC and Diagonal AC and BD intersect each other at O.
To prove: Area (AOD) = Area (BOC)
Proof: ΔADC and ΔBDC are on the same base DC and between same parallel AB and DC.
∴Area (ΔADC) = Area (ΔBDC) [triangles on the same base and between same parallel are equal in area]
Subtract Area (ΔDOC) from both side
Area (ΔADC) – Area (ΔDOC) = Area (ΔBDC) – Area (ΔDOC)
Area (ΔAOD) = Area (ΔBOC)
Hence proved.
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