Diagonals PR and QS of quadrilateral PQRS intersect each other at A show that ar (trianglePSA) × ar (triangle QAR ) = ar ( triangle PAQ ) × ar ( triangle SAR ) l Share with your friends Share 34 Pooja Khanna answered this Refer the link: https://www.meritnation.com/ask-answer/question/diagonals-ac-and-bd-of-a-quadrilateral-abcd-intersect-each/areas-of-parallelograms-and-triangles/6294695 7 View Full Answer