Differentiate (1-3)​√x2+2 / (x+3)​√x-1 w.r.t.x

We have,    y = x-3x2+2x+3x-1log y = logx-3x2+2x+3x-1log y = log x-3 + 12logx2+2 - logx+3 - 12 logx-11ydydx = 1x-3 + 2x2x2+2 - 1x+3 - 12x-1dydx = y1x-3 + xx2+2 - 1x+3 - 12x-1dydx = x-3x2+2x+3x-11x-3 + xx2+2 - 1x+3 - 12x-1

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