Differentiate (1-3)√x2+2 / (x+3)√x-1 w.r.t.x Share with your friends Share 0 Rajat Sethi answered this We have, y = x-3x2+2x+3x-1⇒log y = logx-3x2+2x+3x-1⇒log y = log x-3 + 12logx2+2 - logx+3 - 12 logx-1⇒1ydydx = 1x-3 + 2x2x2+2 - 1x+3 - 12x-1⇒dydx = y1x-3 + xx2+2 - 1x+3 - 12x-1⇒dydx = x-3x2+2x+3x-11x-3 + xx2+2 - 1x+3 - 12x-1 0 View Full Answer