Differentiate :-1] exloga +ealoga+ealogx 2] elog (logx) .log3x Share with your friends Share 4 Ajanta Trivedi answered this since eloga=a 1. the given function is y=ex.loga+ealoga+ealogxy=elogax+elogaa+elogxay=ax+aa+xa .......(1)differentiating eq(1) wrt x:dydx=ddx.(ax)+ddx.(aa)+ddx.(xa) [let ax=t⇒x.loga=logt⇒loga=1t.dtdx⇒dtdx=t.logadydx=ax.loga+0+a.xa-1=ax.loga+a.xa-1 2. the given function is y=elog(logx).log3x i.e.y=(logx).(log3x) [which is product of two functionsdydx=(logx).ddx.(log3x)+[ddx(logx)][log3x]=(logx).13x.3+1x.log3x=logxx+log3xx=logx+log3xx=log(x.3x)x=log(3x2)x hope this helps you 6 View Full Answer
