Dear student,d(3x+2)dx=d(3x)dx+d(2)dx=3dxdx+0 (since, derivative of constant is zero)=(3×1)+0 (since, dxdx=1)=3+0=3Regards!

Differentiate ? 3x+2

D e a r s t u d e n t, \frac{d (3 x + 2)}{d x} = \frac{d (3 x)}{d x} + \frac{d (2)}{d x} = 3 \frac{d x}{d x} + 0 (\sin c e, d e r i v a t i v e o f c o n s \tan t i s z e r o) = (3 \times 1) + 0 (\sin c e, \frac{d x}{d x} = 1) = 3 + 0 = 3 R e g a r d s!