Differentiate the following equation:

log (x2+x +1/x2 - x + 1)

Dear Student,

Please find below the solution to the asked query:

y = logx2+x+1x2-x+1y = log x2+x+1 - log x2-x+1dydx = 2x+1x2+1-x-2x-1x2+1+xdydx = 2x+1x2+x+1-2x-1x2-x+1x4+1+2x2-x2dydx = 2x3+2x2+2x+x2+x+1-2x3-2x2+2x-x2+x-1x4+1+x2dydx = 2x3+3x2+3x+1-2x3+3x2-3x+1x4+x2+1 = 6x2+2x4+x2+1

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