Differentiate w r t x: log(cosecx-cotx) - Maths - Continuity and Differentiability

Question

Differentiate w r t x:
log(cosecx-cotx)

Abhishek Kr. Jha · Accepted Answer

Differentiating logcosecx-cotx wr t x;
ddxlogcosecx-cotx= dlogcosecx-cotxdcosecx-cotx×dcosecx-cotxdx= 1cosecx-cotx×ddxcosecx-ddxcotx       {Since; ddxlogx = 1x}= 1cosecx-cotx×-cosecxcotx--cosec2x       {ddxcosecx = -cosecxcotx and ddxcotx = -cosec2x}= 1cosecx-cotx×cosec2x-cosecxcotx= cosecxcosecx-cotxcosecx-cotx= cosecx

Differentiate w.r.t x: log(cosecx-cotx)

Differentiate w.r.t x:

log(cosecx-cotx)