differentiate with respect to x: x^sinx + (sinx)^cosx Share with your friends Share 0 Shobhit Mittal answered this Dear Student, y=xsinx+sinxcosxdy/dx=sinxxsinx-1cosx+cosxsinxcosx-1-sinx=sinxxsinx-1cosx-sinxcosxsinxcosx-1-sinxdy/dx=sinxcosxxsinx-1-sinxcosx-1REgards 0 View Full Answer
