differintiate e2x Sin3x Cos4x[ Hint given in the solution is 2sin3xcos4x = sin7x - sinx by std trignometry formulaeAs i understand Sin2A = 2SinACosA . Therefore 2sin3xcos3x = sin6xSo as given in hint 2sin3xcos4x should it be corrected to2sin3xcos3x (cos3x in place of cos4x)Correct me if i am wrong.] Share with your friends Share 3 Varun.Rawat answered this Let y = e2x cos 4x . sin 3x⇒y = 12e2x2 cos 4x . sin 3x⇒y = 12e2xsin4x+3x - sin4x-3x⇒y = 12e2xsin 7x - sin x⇒y = 12e2x . sin 7x - e2x . sin x⇒dydx = 12e2x . 7 cos 7x + sin 7x . 2 e2x - e2x . cos x - sin x . 2 e2x ⇒dydx = e2x27 cos 7x + 2 sin 7x - cos x - 2 sin x 0 View Full Answer
