distance of a chord AB from the centre of the circle is 4cm.if the length of a chord AB is 6cm,then find the diameter of the circle
Dear Student!
Let the radius of the circle be r cm.
AB is the chord of the circle and O is the centre of the circle.
Given, AB = 6 cm, OD ⊥AB and OD = 4 cm
OD ⊥ AB,
(Perpendicular from the centre of a circle to a chord bisects the chord)
In right ΔODA,
OA2 = AD2 + OD2
Radius of the circle, OA = 5 cm
∴ Diameter of the circle = 2 × Radius of the circle = 2 × 5 cm = 10 cm
Cheers!