Divide (i) 24xy2z3 by 6yz2 (ii) 63a2b2c3

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1.

 

= 4xyz

2.

This question appears to be incomplete. You have not mentioned the divisor in the question. Recheck your question and do get back to us.

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ANS(i) (24xy2z2) /6yz2

= 4xy

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(i) 24 xy2z3 / 6yz2

=4xyz

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