Hello Khushboo dear, here is the needed figure
Let the point of pivot be at a distance x as shown in the figure
Then taking moments
Anticlockwise moments
20(40+x) + 30(30+x) + 60 x
And clockwise moments
80 (40 - x)
As scale remains horizontal, both clockwise and anti clockwise moments are equal
Equating and solving we have 190 x = 3200 - 1700
So x = 1500/190 = 150/19 = 7.89 cm
Hence point of pivot has to be at a distance (approx) 7.9 cm right from 50 cm
So the point is almost at 57.9 cm
