"DO NOT SEND ANY LINKS" Q In the given figure AB = AC; angle A = 50 degree - Maths - Congruency of Triangles

Question

"DO NOT SEND ANY LINKS"
Q In the given figure AB = AC; angle A = 50 degree and angle ACD =
15 degree Show that BC = CD

Rishabh Mittal · Accepted Answer

Dear Student ,

Please find below the solution to the asked query :

In △ACD, using angle sum property∠DAC + ∠ACD + ∠CDA=180°50° + 15° + ∠CDA=180° ∠CDA=115°∠CDA + ∠BDC = 180°                Linear Pair 115° + ∠BDC = 180°∠BDC = 65°AB = AC     Given ∠ABC = ∠ACB              Angle opposite to equal sides are equal In △ABC,∠ABC + ∠ACB   + ∠BAC=180°∠ABC + ∠ABC   + 50°=180°2 ∠ABC =130°∠ABC=65°∠ABC=∠BDC = 65°⇒ BC = CD                       Sides opposite to equal angles are equal Hence Proved
Hope this information will clear your doubts about the topic
If you have any more doubts just ask here on the forum and our
experts will try to help you out as soon as possible

Regards

"DO NOT SEND ANY LINKS". Q. In the given figure AB = AC; angle A = 50 degree and angle ACD = 15 degree. Show that BC = CD.

"DO NOT SEND ANY LINKS".
Q. In the given figure AB = AC; angle A = 50 degree and angle ACD = 15 degree. Show that BC = CD.