Dear student, Here is the solution of your asked query: Assuming x=3+22 ⇒1x=13+22×3-223-22=3-2232-222=3-22 So now we have to find the value of x-1x x-1x2 = x+1x-2×x×1x =x+1x-2 =3+22+3-22-2 = 4⇒x-1x=2 Regards

Do the 6 question

Do the 6 question 6. (E) None of these ( 3+2Ui— Find the value of (E) None of these CLASS-9 3-20)

Dear student,
Here is the solution of your asked query:

Assuming x = 3 + 2 \sqrt{2} \Rightarrow \frac{1}{x} = \frac{1}{3 + 2 \sqrt{2}} \times \frac{3 - 2 \sqrt{2}}{3 - 2 \sqrt{2}} = \frac{3 - 2 \sqrt{2}}{3^{2} - {(2 \sqrt{2})}^{2}} = 3 - 2 \sqrt{2} So now we have to find the value of \sqrt{x} - \frac{1}{\sqrt{x}} . {(\sqrt{x} - \frac{1}{\sqrt{x}})}^{2} = x + \frac{1}{x} - 2 \times \sqrt{x} \times \frac{1}{\sqrt{x}} = x + \frac{1}{x} - 2 = 3 + 2 \sqrt{2} + 3 - 2 \sqrt{2} - 2 = 4 \Rightarrow \sqrt{x} - \frac{1}{\sqrt{x}} = 2

Regards

-9

View Full Answer

Do the 6 question Do the 6 question 6. (E) None of these ( 3+2Ui— Find the value of (E) None of these CLASS-9 3-20)

Do the 6 question

Do the 6 question 6. (E) None of these ( 3+2Ui— Find the value of (E) None of these CLASS-9 3-20)