Solution: M∞ = L Df0 fe 400 =20 × 250 5 × f e ⇒ fe =20 × 250 5 ×400 fe= 2 5cm option 3 is correct

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Solution:

M_{\infty} = \frac{L D}{f_{0} f_{e}} 400 = \frac{20 \times 25}{0.5 \times f e} \Rightarrow f_{e} = \frac{20 \times 25}{0.5 \times 400} f_{e} = 2.5 c m

option 3 is correct

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