draw a rough sketch of two triangles such that they have five pairs of congruent parts but still the triangles are not congruent?

 its not possible

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not possible

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  In ΔABC and ΔMNO

 AB = MN = 5 cm
 AC = MO = 5 cm
 ∠A = ∠M = 50º
 ∠B = ∠N = 60º
 ∠C = ∠O = 70º
 BC ≠ NO

Thus, in two triangles they have five pairs of congruent pats are equal, but they are not congruent.

 

  • 4
let, abc and def be two triangles
let, ab=de
bc=ef and all angles are equal
also, ac!=df (ac does not equal to df)
​(now, you can 'attempt' to prove the triangles congruent by SAS (or AA ) but since you cannot prove them SSS they are NOT congruent)
  • 4
IN ABC AND PQR 
   
AB=PQ
AC=PR
(ANGLE)A=​(ANGLE)R
(ANGLE)B=​(ANGLE)P
(ANGLE)C=​(ANGLE)Q
and        BC is not equal to  QR
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first draw 2 triangles with 3 angles same and 2 sides same but their size should be different.this is how the triangle will be congruent but wont be congruent
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It is not possible to draw such a triangle
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thanx
  • -1
It is not possible to draw such a triangle
  • 0
It is never possible to have such a triangle
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Let abc and def be two triangles
so, ab=de
and
bc=ef all angles are equal
(now, you can attempt to prove the triangles congruent by SAS or AA but since you cannot prove them SSS they are not corgruent.)
thumps up if it helps!!!
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hh
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Hahaha
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Post another question
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It is not posiable
  • -2
This is not possible as other congruent rule will make two figures congruent.
  • -2
Google
  • 0
Please find this answer

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Please find this answer

  • 0
Hdl
  • -2
Fj
  • -4
It is never possible to have such a triangle
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ITS NOT POSSIBLE DEAR
 ITS A MENTAL MATHS QUESTION.
I THINK YOU SHOULD ASK THIS FROM OUR MERITNATION EXPERTS.
  • 1
I know its right question if you did not understand till now please comment ..... Its too simple
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It is NOT POSSIBLE to draw  such a triangle]
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it is impossible
  • -2
not possible
  • -2
                   t
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It is not possible to draw such a traingle.
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dont know
  • 0
not possible
  • 1
can you pls provide me a pencil
  • 0
Negative
  • 0
It is not posssible
  • 0
It is not possible
  • 0
IN ABC AND PQR?
? ?
AB=PQ
AC=PR
(ANGLE)A=?(ANGLE)R
(ANGLE)B=?(ANGLE)P
(ANGLE)C=?(ANGLE)Q
and ? ? ? ?BC is not equal to ?QR
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pojh
  • 0
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