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Draw a triangle ABC with side BC=3.5 cm,angle B=60 degrees,altitude AD=2.5 cm . Then,draw another triangle AB'C' similar to triangle ABC such that each side of AB'C' is 2 times that of the corresponding side of triangle ABC.Please write the steps of construction

your question seems to be written wrong. so if your question is:

Construct an isosceles triangle whose base BC=3.5cm and altitude,AD=2.5 cm and then another triangle whose side are 3/2  times the corresponding sides of the isosceles triangle.

 

then the solution for the above is given in the following similar link:

http://cbse.meritnation.com/study-online/ncert-solutions/math/9/2215/constructions/construct-an-isosceles-triangle-whose-base-i

 

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Follow this steps...Hope it helps!!pls gV thumbs Up IF u lyk:):)

Steps of Construction

Step 1: Draw a line segment AB = 8 cm.

Step 2: Draw a perpendicular bisector of AB. It intersects AB at O, take O as a centre and cut OC = 4 cm.

Step 3: Join A to C and B to C. ABC is the required isosceles triangle.

Step 4: From A draw AX an acute angle and draw A1, A2, A3 such that AA1 = A1A2 = A2A3.

Step 5: Join A2 to B.

Step 6: Through A3 draw A3B’ parallel to A2B. It intersects AB after extending at B’.

Step 7: Through B’ draw B’C’ parallel to BC on extending AC. It intersects AC at C’.

AB’C’ is the isosceles triangle whose side is 3/2 of the given ABC.

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