Draw a triangle with vertices o(0,0)A(6,0)B(6,2).Classify the triangle and also find its area ?

Answer :

We can draw Points O ( 0 , 0 ) , A ( 6 , 0 )  and  B ( 6 , 2 ) , On x - y plane , As  :



Now we can see that $∆$ OAB is a right angle triangle  , As $\angle$ OAB  =  90$°$ . 

We know Area of triangle  = $\frac{1}{2}$ ( Base ) ( Height )

Here Base  OA  =  6  unit 

And

Height  AB  =  2 unit  , So

Area of $∆$ OAB = $\frac{1}{2}$ ( 6 ) ( 2 )  =  6  unit²  ( Ans )