draw an equilateral triangle ABC and using compasses and ruler construct a perpendicular from the vertex a to the side BC.
Answer :
We follow these steps :
Step 1 : Draw a line BC
Step 2 : take radius = BC and center B and C draw two arcs these arcs intersect at " A " .
Step 3 : Join AB and AC , we get required equilateral triangle ABC .
Step 4 : With same radius and center " A " draw two arcs these arcs intersect our line BC at " B " and " C " . Now with same radius and center " B and C draw two arcs these arcs intersect at " D " .
Step 5 : Join AD that intersect our line BC at " M " . So AM is perpendicular on BC .
We follow these steps :
Step 1 : Draw a line BC
Step 2 : take radius = BC and center B and C draw two arcs these arcs intersect at " A " .
Step 3 : Join AB and AC , we get required equilateral triangle ABC .
Step 4 : With same radius and center " A " draw two arcs these arcs intersect our line BC at " B " and " C " . Now with same radius and center " B and C draw two arcs these arcs intersect at " D " .
Step 5 : Join AD that intersect our line BC at " M " . So AM is perpendicular on BC .