draw the graph of 2x+y=6 and 2x-y+2=0.shade the regions bounded by these lines at x axis.find the area of shaded region.

sorry by mistake i have putted thumb down. it's really good answer.

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6(ax+by)=3a+ab ; 6(bx-ay)=3b-2a find x and y
 
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y did u multiply 2nd equation by 2
 
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Can anyone give the full answer for this question plzz I didn't understood 😊
 
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IN FIRST EQUATION
TAKE x=1 THAT MEAN y=4
x=2  i.e. y=2 
MARK THE POINT OF BOTH EQUATION ON THE GRAPH

 
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Given equations are:

2x + y – 6 = 0 ... (1)

2x – y + 2 = 0 ... (2)

Solution for 2x + y – 6 = 0 are (2, 2), (0, 6) and (3, 0).

Solution for 2x – y + 2 = 0 are (2, 6), (1, 4) and (3, 8).

The graph for the equations can be drawn as follows:

 

Co-ordinates of vertices are (1, 4), (-1, 0) and (3, 0).

Area = (½)x base x height

       = (1/2) x 4 x 4

       = 8 sq units
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Given equations are:

2x + y – 6 = 0 ... (1)

2x – y + 2 = 0 ... (2)

Solution for 2x + y – 6 = 0 are (2, 2), (0, 6) and (3, 0).

Solution for 2x – y + 2 = 0 are (2, 6), (1, 4) and (3, 8).

The graph for the equations can be drawn as follows:

 

Co-ordinates of vertices are (1, 4), (-1, 0) and (3, 0).

Area = (½)x base x height

       = (1/2) x 4 x 4

       = 8 sq units
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👍👍👍👍
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How do you find solutions.. Plz tell
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Sandesh G has answered the question correctly.
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