Draw two ogives for the following distribution and also find median.

 

Marks0-1010-2020-3030-4040-5050-6060-7070-80
Frequency4101622201882
CF4143052729098100

 

Total no. of terms = 100,  which is even.

 

Median = 

 

 

Less than Type

More than Type

Marks

Cumulative frequencies

Marks

Cumulative frequencies

Less Than 10

4

More Than 0

100

Less Than 20

14

More Than 10

100-4=96

Less Than 30

30

More Than 20

96-10=86

Less Than 40

52

More Than 30

86-16=70

Less Than 50

72

More Than 40

70-22=48

Less than 60 90More than 5048-20=28
Less than 70 98More than 6028-18=10
Less than 80 100More than 7010-8=2

 

 

More than 80

2-2=0

 

Similarly, you can draw the less than ogive.

 

 

  • -3

Marks Frequency

0-10 410-20 1020-30 1630-40 2240-50 2050-60 1860-70 870-80 2
  • -1

sorry i cant post the graph but the table is

less then10 4

less then20 14

less then30 30

less then40 52

less then50 72

less then60 90

less then70 98

less then80 106

  • -2
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