During the electrolysis of water 4 mol of electrons were transferred from anode to cathode. the total volume of gases produced at STP will be approximately

During electrolysis the reaction occurs as:
  H2O ---> H2 + 1/2O2 
1mol ......... 1mol... 0.5 mol

So, we see that,
1 mole water releases = 1 mole H2 gas = 22.4 L H2 gas
Since, 1 mole of water requires = 2moles of electrons
So, 2 moles of electrons produces = 22.4 L H2 gas
Hence, 4 moles of electrons will produce = (22.4/2) x 4 = 44.8 L H2 gas
Similarly, 4 moles of electrons will produce = (11.2/2) x 4 = 22.4 L O2 gas
Hence, ttal volume of gases at STP = 44.8+ 22.4 = 67.2 L
 

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