E is an exterior point on diagonal AC of a parallelogram ABCD and DC produced meets BE at F. If side BC produced meets DE at G, prove that DB is parallel to GF

Given that:  ABCD be a parallelogram and E is an exterior point on diagonal AC.
To Prove: DB is parallel to GF
Construction: Join GF and DB


Proof:
In ΔABE,CF||AB            because, CD||ABBy basic proportionality theorem,EFFB=ECCA      .....1Similarly, In ΔADE,CG||AD         because, BC||ADBy basic proportionality theorem,EGGD=ECCA      .....2from 1 and 2,EFFB=EGGDDB||GF  by converse of basic proportionality theoremHence Proved.

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