Each edge of an equilateral triangle is 'a' cm. A cone is formed by joining any two sides of the triangle. What is the volume (in cm3) of the cone?
(A) a 2 24 π 3 4 - π 2              (B) a 3 24 π 2 4 π 2 - 1             (C) a 3 8 π 2 1 - 4 π 2             (D) a 3 3 π 2 1 - 2 π

Base C of Cone = a cm,    Slant Height = a cm
Thus 2Pie R  = a   or    R = a/2Pie cm
Slant Height2  -  (R)2 =  Height2.
Thus H = Root(a2 -R/22.) = Root(a2 - a2/(4PIE2)
Volume = 1/3PIE R2H
            =1/3 PIE(a/2PIE)2 * Root [a2 -a2/(4PIE2].
            =1/3 PIE*a2/4PIE2 * Root [(4PIE2a2 - a2)/4PIE2]
            = 1/3(a2/4PIE) * a/2PIE * Root(4PIE2 - 1)
            = 1/24(a2/PIE2)Root(4PIE2 - 1)   ANSWER B
  • -1
What are you looking for?