Each edge of an equilateral triangle is 'a' cm. A cone is formed by joining any two sides of the triangle. What is the volume (in cm3) of the cone?
(A) (B) (C) (D)
Base C of Cone = a cm, Slant Height = a cm
Thus 2Pie R = a or R = a/2Pie cm
Slant Height2 - (R)2 = Height2.
Thus H = Root(a2 -R/22.) = Root(a2 - a2/(4PIE2)
Volume = 1/3PIE R2H
=1/3 PIE(a/2PIE)2 * Root [a2 -a2/(4PIE2].
=1/3 PIE*a2/4PIE2 * Root [(4PIE2a2 - a2)/4PIE2]
= 1/3(a2/4PIE) * a/2PIE * Root(4PIE2 - 1)
= 1/24(a2/PIE2)Root(4PIE2 - 1) ANSWER B
Thus 2Pie R = a or R = a/2Pie cm
Slant Height2 - (R)2 = Height2.
Thus H = Root(a2 -R/22.) = Root(a2 - a2/(4PIE2)
Volume = 1/3PIE R2H
=1/3 PIE(a/2PIE)2 * Root [a2 -a2/(4PIE2].
=1/3 PIE*a2/4PIE2 * Root [(4PIE2a2 - a2)/4PIE2]
= 1/3(a2/4PIE) * a/2PIE * Root(4PIE2 - 1)
= 1/24(a2/PIE2)Root(4PIE2 - 1) ANSWER B