Electrochemistry mains online 2018:

$$\begin{gathered} Q. 38 Given \\ \left(i\right) 2F{e}_2{O}_3\left(s\right)\to 4Fe\left(s\right)+3O_2\left(g\right); \\ {△}_{r}G°=+1487.0 kJ mo{l}^{-1} \\ \left(ii\right) 2CO\left(g\right) + O_2\left(g\right)\to 2C{O}_2\left(g\right); \\ {△}_{r}G°=+1-514.4 kJ mo{l}^{-1} \\ Free energy chane, {△}_{r}G° for the reaction \\ 2F{e}_2{O}_3\left(s\right)+6CO\left(g\right)\to 4Fe\left(s\right)+6C{O}_2\left(g\right) will be: \\ Options \\ 1. -112.4 kJ mo{l}^{-1} \\ 2. -56.2 kJ mo{l}^{-1} \\ 3. -208.0 kJ mo{l}^{-1} \\ 4. -168.2 kJ mo{l}^{-1} \end{gathered}$$