Electrolysis of a metal salt solution resulted in the deposition of 1 gram of metal by passing 1 5 amperes - Chemistry - The p-Block Elements

Question

Electrolysis of a metal salt solution resulted in the deposition of
1 gram of metal by passing 1 5 amperes for 2 hours Determine the
charge carried by the metal ion (Atomic mass of the metal = 27)

Vartika Jain · Accepted Answer

Dear Student,

Let the charge on metal be n+The reduction half-reaction would then be,    Mn+  + ne-  →  M1 mol     n mol        1 mol=27 gThe quantity of electricity required to deposit 27 g metal = n mol of electron                                                                                               = n×96500 CTherefore, 1 g metal will be deposited by =n×96500×127= n×3574
07 C of electricityThe electricity actually passed= I×t= 1
5×2×60×60 CTherefore, 1
5×2×60×60 C = n×3574
07 Cor, n=1 5×2×60×603574
07≈3Therefore, charge on metal ion= +3

Electrolysis of a metal salt solution resulted in the deposition of 1 gram of metal by passing 1.5 amperes for 2 hours. Determine the charge carried by the metal ion. (Atomic mass of the metal = 27)