Electrolysis of a solution of HSO4 --ions produces S2O8 -- .Assuming 75% current efficiency what current should be employed to achieve a production rate f 1 mole of S2O8 --per hour?
Dear Hardee Shah,
For the production of 1 mole of S2O8 2- from HSO4- exchange of 2 e takes place. Hence 2 Faraday is required of 100% efficiency.
But for 75% efficiency we require 2.67 Faraday per second for the production of 1 mole of S2O8 2-
Regards
For the production of 1 mole of S2O8 2- from HSO4- exchange of 2 e takes place. Hence 2 Faraday is required of 100% efficiency.
But for 75% efficiency we require 2.67 Faraday per second for the production of 1 mole of S2O8 2-
Regards