electron present in single electron specie jumps from level 3 to 1.emitted photons when passed through a sample containing excited He+ion causes further excitation to some higher energy level.Determine atomic number of single electron specie.

Dear Student,

In case of single electron specie, E=-13.6×Z2(1n12-1n22)n1= 3 and n2=1So,E=-13.6×Z2(132-112) ...(i)In case of He+E=-13.6×Z2(1n12-1n22)So,E=-13.6×22(1n12-1n22) ...(ii)Z can be calculated further from (i) and (ii).

  • -4
three
  • -3
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