emf of the cell reaction 3Sn4+ + 2Cr-- 3Sn2+ + 2Cr3+ is 0 89 V Calculate delta G {F=96500 - Chemistry - Electrochemistry

Question

emf of the cell reaction 3Sn4+ + 2Cr--> 3Sn2+ + 2Cr3+ is 0 89 V
Calculate delta G {F=96500 C+mol and VC=J}

Vartika Jain · Accepted Answer

Dear Student,

∆G°=-nFE°Here, E°=0
89 VAt cathode: Sn4+ + 2e-→ Sn2+  
(i)At anode: Cr → Cr3+ + 3e-   
(ii)Multiplying (i) by 3 and (ii) by 2 and adding both, we get 3Sn4+ + 2Cr→ 3Sn2+ +2 Cr3+ Here, n=6So, ∆G°=-6×96500×0
89 = -515 3 kJ

emf of the cell reaction 3Sn4+ + 2Cr--> 3Sn2+ + 2Cr3+ is 0.89 V.Calculate delta G.{F=96500 C+mol and VC=J}