Energy of photon in eV having wavelength 124 Armstrong will be ( h=6.6?10^-34) Share with your friends Share 0 Animesh Paul answered this Dear student, Wavelength (λ) = 124 A0 E = hcλ = 6.6 × 10-34 × 3 × 108124 × 10-10 = 0.1596 × 10-16 JEnergy in eV = 0.1596 × 10-161.6 × 10-19 = 99.75 eV Regards 0 View Full Answer