Equal moles of hydrogen and oxygen gases are placed in a container with a pin hole through which both can escape what fraction of the oxygen escapes in time required for one half of the hydrogen to escape

By Graham's law of diffusion, t2/t1 = (M2/M1)^1/2 t2/t1 = (32/2)^1/2 t2/t1 = (16/1)^1/2 t2/t1 = 4 t2 = 4t1 Therefore, 1 molecule of oxygen takes same time to escape as that of 4 molecules of Hydrogen Hence time taken by X molecules of oxygen to escape in the same time required by 1/2 of Hydrogen to escape = (1/2) x ( 1/4) = 1/8

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