. Equal weight of ?X? (At. wt. = 36) and ?Y? (At. wt. = 24) are reacted to form the compound X2Y3. Then :
(A) X is the limiting reagent?
(B) Y is the limiting reagent
(C) No reactant is left over?
(D) Mass of X2Y3 formed is double the mass of ?X? taken?

Dear student,

$2X+3Y\to X_2{Y}_3$
molar mass of X₂Y₃ =144 gm
there are equal amounts of X and Y present .Let us consider 1 gm each of X and Y are present.
From the equation we see that 2 moles of X reacts with 3 moles of Y.

2 moles of X=72 gm
3 moles of Y= 72 gm 


72 gm of X produces  144 gm of X₂Y₃
so 1 gm produces $\frac{144}{72}\times 1=2 gm$
72 gm of Y produces 144 gm of X₂Y₃
so 1 gm produces $\frac{144}{72}\times 1=2 gm$
since both reactants are present in equal amounts hence none is a limiting reagent.
Hence statement (c) No reactant is left over (d) Mass of X₂Y₃ is double the mass of 'X' taken.
Regards!