Equation of parabola with focus(F)at(-a,0):directrix is x=a P(-x,y) is a point on parabola, equidistant from (-a,0)and B(a,y) NowPF=PB Using - Maths - Conic Sections

Question

Equation of parabola with focus(F)at(-a,0):directrix is x=a P(-x,y)
is a point on parabola, equidistant from (-a,0)and B(a,y) NowPF=PB
Using distance formula we get, y^2=4ax, but equation is y^2=-4ax

Arnab Gupta · Accepted Answer

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Equation of parabola with focus(F)at(-a,0):directrix is x=a. P(-x,y) is a point on parabola, equidistant from (-a,0)and B(a,y).NowPF=PB Using distance formula we get, y^2=4ax, but equation is y^2=-4ax