Equivalent wt. of KMnO4 when it is converted into MnSO4 is:

1. m/5
2. m/6
3. m/3
4. m/2

The equivalent weight of an oxidising or a reducing agent is defined as the mass of the substance that gains or accepts one mole of electrons in a reaction. A general equation would therefore be written as

= molar mass of salt / number of electrons gained or lost by one molecule

Here we are given that KMnO₄ is being converted to MnSO₄. Manganese in KMnO₄ is in +7 oxidation state, while in MnSO₄ it is in +2 oxidation state. Therefore here it is accepting 5 electrons. 

 Mn⁺⁷ + 5e^- → Mn⁺²

So the equivalent weight here would be m/5

So the correct answer is (1) m/5