estimate the total number of electrons present in 100g of water. how much is the total negative charge carried by these electrons? A vogadro's number =6.02*10 to the power 23 and molecular mass of water= 18.
no. of moles of water =given mass / molar mass = 100/18 = 50/9 moles
total no. of atoms in 100g of water = 6.022 *1023 * 50/9 = 3.455 *1024 atoms
no. of electrons in 1 atom of H2O = 2*1 +8 = 10
total no. of elctrons = 3.455*1024 *10 = 3.455*1025 electrons..
charge in 1 electron = 1.6 *10-19
charge carried by 3.455*1025 electrons = 1.6*10-19 * 3.455*1025 = 5.528 * 106