evaluate 13 sigma n=1(in +in+1)where is nbelongs to N. n n+1 are in power . Share with your friends Share 3 Kulwinder answered this Answer=(-1+I) -11 View Full Answer Ramji Shukla answered this RS Sharma ex. 3 complex numbers 0 Lazarlazar answered this 1+sin * x n =7 cause n cancels out and sin becomes six because of multiplied x and then 1+ six is seven -6