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Evaluate:
(27/8)^2/3 - (1/4)^-2 + 5⁰

H i, {(\frac{27}{8})}^{\frac{2}{3}} - {(\frac{1}{4})}^{- 2} + 5^{0} = {(\frac{3^{3}}{2^{3}})}^{\frac{2}{3}} - {(4^{- 1})}^{- 2} + 1 = {(\frac{2}{3})}^{3 \times \frac{2}{3}} - 4^{- 1 \times - 2} + 1 = {(\frac{2}{3})}^{2} - 4^{2} + 1 = \frac{4}{9} - 16 + 1 = \frac{4}{9} - 15 = \frac{4 - 135}{9} = \frac{- 131}{9}

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