Evaluate Cos(2arc Cos x + arc Sin x) at x = (1/5) 13 j 8 Evaluate cos(2cos x - Maths - Inverse Trigonometric Functions

Question

Evaluate Cos(2arc Cos x + arc Sin x) at x = (1/5)

Ankita Agarwal · Accepted Answer

Dear Student,

cos 2 cos-1x+sin-1xcos cos-1x+sin-1x+cos-1xUsing: cos-1x+sin-1x=π2cos π2+cos-1xWe know, cosπ2+A= -sin A⇒ -sin cos-1x cos-1x=sin-11-x2⇒ -sin sin-11-x2⇒ -1-x2 Substituting x= 15, we get⇒ -1-125⇒ -2425⇒ -265

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Evaluate Cos(2arc Cos x + arc Sin x) at x = (1/5). Evaluate Cos(2arc Cos x + arc Sin x) at x = (1/5). 13 j 8. Evaluate cos(2cos x + sin x) at x = 1/5

Evaluate Cos(2arc Cos x + arc Sin x) at x = (1/5).

Evaluate Cos(2arc Cos x + arc Sin x) at x = (1/5). 13 j 8. Evaluate cos(2cos x + sin x) at x = 1/5