Login

evaluate cos[sin^-11/4 + sec^-1 4/3]

$cos [\sin^{- 1} \frac{1}{4} + \sec^{- 1} \frac{4}{3}] {Let sin}^{- 1} \frac{1}{4} = x \sin x = \frac{1}{4} \cos x = \frac{\sqrt{15}}{4} \sec y = \frac{4}{3} \cos y = \frac{3}{4} \sin y = \frac{\sqrt{7}}{4} ∴ \cos [\sin^{- 1} \frac{1}{4} + \sec^{- 1} \frac{4}{3}] = \cos (x + y) = \cos x \cos y - \sin x \sin y = (\frac{\sqrt{15}}{4}) (\frac{3}{4}) - (\frac{1}{4}) (\frac{\sqrt{7}}{4}) = \frac{3 \sqrt{15} - \sqrt{7}}{16}$

40

View Full Answer

Copyright © 2024 Aakash EduTech Pvt. Ltd. All rights reserved.

Aakash EduTech Pvt. Ltd.

What are you looking for?